Question

The weight of an iron ball on earth is 12 kg. Its weight on moon will be

Answer 1

Final answer = 1.9 Kg or 2Kg aprox

Weight = Mass * Gravitational Force

Weight of Iron Ball {12} = Mass * Gravity on Earth{9.8}

12 = Mass * 9.80  

Mass = 12/(9.8)

Mass = 1.2

So its weight on Moon would be

Weight = 1.2 * 1.62

Weight on Moon = 1.9 Kg aprox

So we can estimate it to be 2 kg also as per your wish..

Please verify the calculations once as I am not good at calculations..

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Answer 2

Answer:

The weight of the object on Moon = 19.6N

Explanation:

Step 1:  Acceleration due to gravity:

The acceleration achieved by any object due to the gravitational force of attraction by any planet is called acceleration due to gravity by the earth. As each planet has a different mass and radius so the acceleration due to gravity will be different for a different planet,

Step 2: Weight:

The weight (w) of an object is the force of gravity on the object and may be defined as the mass $(\mathrm{m})$ times the acceleration of gravity $(\mathrm{g})$.

Weight is a force, the SI unit of weight is Newton.

Weight $(W)=m g$

Where m is mass and g is the acceleration due to gravity.

The mass of the moon is $1 / 100$ times and the radius of the moon is $1 / 4$ times that of the earth.

Since the acceleration due to the gravity of the moon is one-sixth of that of the earth.

So Weight of any object on the Moon $=1 / 6 \times$ Weight of any object on the Earth surface.

Step 3: Calculation:

Given that,

Mass of the object

$(\mathrm{m})=12 \mathrm{~kg}$

g on earth =$9.8 \mathrm{~m} / \mathrm{s}^2$

gravity on moon = $g^{\prime}=g / 6$

∴ The weight of the object on moon = $\mathrm{mg}^{\prime}=\mathrm{mg} / 6=(12 \times 9.8) / 6=19.6 \mathrm{~N}$

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