Question

The weight of an object is more at the poles than at the equator. At which of these can we get more sugar for the same weight? State the reasons for your answer.

Answer 1

Let $g_p$ is the acceleration due to gravity at pole and $g_e$ acceleration due to gravity at equator.

weight of the object at pole ,$W_p=mg_p$
weight of the object at equator, $W_e=mg_e$

a/c to question,
weight of the object at pole > weight of the object at equator.

e.g., $m_pg_p>m_eg_e$

We know that, $g_p>g_e$ then, $m_e>m_p$

Hence, we can get more sugar at equator.

Answer 2

Explanation:

Let g_pg

p

is the acceleration due to gravity at pole and g_eg

e

acceleration due to gravity at equator.

weight of the object at pole ,W_p=mg_pW

p

=mg

p

weight of the object at equator, W_e=mg_eW

e

=mg

e

a/c to question,

weight of the object at pole > weight of the object at equator.

e.g., m_pg_p > m_eg_em

p

g

p

>m

e

g

e

We know that, g_p > g_eg

p

>g

e

then, m_e > m_pm

e

>m

p

Hence, we can get more sugar at equator.