Math, asked by ammarmushtaq711, 9 months ago

The weight of goods sold by three hawkers are in the ratios of 3 : 4 : 5. The least amount sold by one of them is 105 kg. Find the total amount that was sold and also calculate the share of each hawker.​

Answers

Answered by SeshankMannuru
0

here is your solution.

Hope it's helpful.

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Answered by kavitapandey21
0

Answer:

3x+4x+5x=12x

Least amount =105kg

3x=105kg

x= 105%3

x=35

Total amount is=12x

12*35=420

The share of each hawkers=3*35=105,4*35=140,5*35=175


kavitapandey21: Good job
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