Question

The weight of H2SO4 present in 400 ml of 0.125M solution is a) 2.45 g b) 3.92 g c) 4.9 g d) 9.8 g

Answer 1

Explanation:

we know,

$molarity = \frac{no. \: of \: moles}{volume}$

Hence, number of moles = molarity × volume

= 0.125 × 0.4 = 0.05 moles.

1 mole H2SO4 = 98 gram.

Hence, 0.05 moles = 98/20 = 4.9 gram.

Regards.

Kshitij

Answer 2

Answer:4.9grams

Explanation:

first find the moles by using no.of moles formula

n=mass of the compound / molar mass

cinvert 400ml into litres 0.4L

then moles will be 0.125×0.4L=0.05moles

then 0.05×98=4.9 grams

thank you.

regards,

Somaskandeswaran iyengar