The weight of the book on the earth is 5Newton what is the weight of the book on a height equal to the radius of the earth
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weight is the force at which the earth pulls the object..
Now,
w=F propotional to 1/D^2
on the surface tha distance is equal to the radius of the earth (R) , when the object is raised to the height of earth's radius the the height becomes 2R... thus shows that the height is doubled so the force will be decreased by (1/2)^2 = 1/4
So the weight of the book
will be
5/4 = 1.25 N
Now,
w=F propotional to 1/D^2
on the surface tha distance is equal to the radius of the earth (R) , when the object is raised to the height of earth's radius the the height becomes 2R... thus shows that the height is doubled so the force will be decreased by (1/2)^2 = 1/4
So the weight of the book
will be
5/4 = 1.25 N
Answered by
0
weight =force proportional to 1/d^2 . when it is on a height =radius the distance becomes twice. W=F=1/(2d)^2=1/4d^2.thus it's weight becomes 1/4×5N=1.25N
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