Math, asked by ANIRUDHSAXENA2894, 1 year ago

The wheel of a railway carriage is 90cm in diameter and makes 3 revolutions in a second; hoe fast is the train going?Sl loney

Answers

Answered by vamshi005
15
the given diameter is 90cm then radii is 45cm
we know circumference of circle is 2πr
circumference=2(45)(22/7)
=282.85
by problem 3 revolutions in 1 second
3×282.85=848.57
so speed = 848.57mps
Answered by Wafabhatt
8

Answer:

The speed is 0.848 m/s

Step-by-step explanation:

Diameter of the wheel 'd' = 90 cm = 0.9 meters

So the radius of that particular wheel 'r' = 90/2 = 45 cm = 0.45 m

Circumference of the wheel = 2*π*r = π*d = π*0.9 = 2.827 m

Number of revolutions that the wheel performs in 1 second = 3

Distance covered by the wheel in 1 second = 3*2.827 = 8.482 m

So the speed of the train will be 0.848 meters/second

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