The wheel of a railway carriage is 90cm in diameter and makes 3 revolutions in a second; hoe fast is the train going?Sl loney
Answers
Answered by
15
the given diameter is 90cm then radii is 45cm
we know circumference of circle is 2πr
circumference=2(45)(22/7)
=282.85
by problem 3 revolutions in 1 second
3×282.85=848.57
so speed = 848.57mps
we know circumference of circle is 2πr
circumference=2(45)(22/7)
=282.85
by problem 3 revolutions in 1 second
3×282.85=848.57
so speed = 848.57mps
Answered by
8
Answer:
The speed is 0.848 m/s
Step-by-step explanation:
Diameter of the wheel 'd' = 90 cm = 0.9 meters
So the radius of that particular wheel 'r' = 90/2 = 45 cm = 0.45 m
Circumference of the wheel = 2*π*r = π*d = π*0.9 = 2.827 m
Number of revolutions that the wheel performs in 1 second = 3
Distance covered by the wheel in 1 second = 3*2.827 = 8.482 m
So the speed of the train will be 0.848 meters/second
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