Question

the wheel of radius 1m rolls forward half a revolution on a horizontal ground. the magnitude of the displacement of the point of the wheel initially in contact with the ground is

Answer 1

Given, the radius of the wheel is 1m. so,its circumference is 2π m

when it rotates half, the initial point of contact is vertically above the final point of contact.thus,the three points form a right triangle.

by pythagoras theorem, we solve it to get the magnitude of displacement,which is the hypotenuse.

thus, d=√4+π²

here's the answer!

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