Question

The whole surface area of a rectangular block is 8788cm2 if the length ,breadth, he ight are in the ratio 4:3:2 find the difference between its length and height

Answer 1

given length : breadth : height = 4 : 3 : 2
let length breadth and height of cuboidal block be 4y,3y,2y
TSA of cuboidal block = 8788 cm²
TSA of cuboidal block = 2(lb + bh + hl)
2(lb + bh + hl) = 8788
2(4y×3y + 3y×2y + 2y×4y)= 8788
12y²+6y²+8y²=8788/2
26y²=4394
y²=4394/26
y²= 169
y²= 13²
y=13

length of cuboidal block= 4y=4×13=52
breath of cuboidal block= 3y=3×13=39
height of cuboidal block= 2y=2×13=26

difference between length and height of cuboidal block = length of cuboidal block - height of the cuboidal block= 52-26= 26

hope it helps....

Answer 2

Answer:

26cm

Explanation:

hi