Math, asked by rahulsinghmar1, 1 year ago

The width of rectangle is 4 cm, if the perimeter must be at least 56 cm find the smallest length it can have?

Answers

Answered by Anonymous
69

Hey\:!!..

The answer goes here....

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》To find -

Smallest length = ?

》Given -

Perimeter = 56 cm

Width = 4 cm

》Solution -

Let the length of the rectangle be x. Now,

Perimeter = 2(l+b)

Perimeter = 2(x+4)

56 = 2(x+4)

56\div 2 = x+4

28 = x+4

x = 24

So, the smallest length a rectangle with perimeter as 56 cm is 24 cm.

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Thanks !!..




rahulsinghmar1: thanks
Answered by ans81
64
 \sf{Hello \: Friend}

 \sf{Here \:is\: your\: answer}
 <big>To find : Length ? </big>

 <b>
Given : width = 4cm

Perimeter = 56 cm

 </b>

 \huge {\fcolorbox{red} {aqua} {Solution :-}}

Perimeter of rectangle = 2(L + B)

56 = 2(L + 4)

56/2 = L + 4

28 = L + 4

28 - 4 = L

24 = Length

 <u><b>⛬, 24 is the smallest length of rectangle </b></u>

 <rule>

Hope it will help you

@thanksforquestion

@bebrainly

prathamsachdeva1112: Let the length of the rectangle be xx . Now,

⇒ PerimeterPerimeter = 2(l+b)2(l+b)

⇒ PerimeterPerimeter = 2(x+4)2(x+4)

⇒ 5656 = 2(x+4)2(x+4)

⇒ 56\div 256÷2 = x+4x+4

⇒ 2828 = x+4x+4

⇒ xx = 2424

So, the smallest length a rectangle with perimeter as 56 cm is 24 cm.
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