the X and Y intercepts of line are 2 and 3 respectively then find the slope of line l
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given, x- intercept of a line = 2 and y - intercept of the line = 3
we know,
standard equation of a line in intercept form is given by, x/a + y/b = 1
where a denotes x - intercept and b denotes y - intercept.
from above a = 2 and b = 3
so, x/2 + y/3 = 1
or, (3x + 2y)/6 = 1
or, 3x + 2y = 6
now, slope of line = -coefficient of x/coefficient of y
= -3/2
hence, slope of line is -3/2
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