Question

The zeroes of p(x) = x^2 - 1 are; option a 1 ,-1 b -1,2 c -2,2 d none of these​

Answer 1

Answer:

a) is right answer

Step-by-step explanation:

p(x) = x²-1

x²-1 = 0

(x+1)(x-1) = 0

x = 1 & - 1

Hope it help:)