Question

there are 6 red balls,8 blue balls and 7 green balls in a bag. if 5 are drawn with replacement, what is the probability at least three are red?

Answer 1

there are 6 red balls,8 blue balls and 7 green balls in a bag. if 5 are drawn with replacement, what is the probability at least three are red is 1/7

Answer 2

Probability of at least three are red is 0.1145 when there are 6 red balls, 8 blue balls and 7 green balls in a bag.

Given that,

There are 6 red, 8 blue balls and 7 green balls in a bag.

We have to find what is the probability at least three are red if 5 are drawn with replacement.

We know that,

The total balls are 6+8+7 = 21 balls

5 ball out of 21 ball are selected

That means ²¹C₅ ways

Probability of at least three are red is

$\frac{^6C_3\times ^{15}C_2+^6C_4\times ^{15}C_1+^6C_5\times ^{15}C_0}{^21C_5}$

= 0.1145

Therefore, Probability of at least three are red is 0.1145.

To know more, visit:

https://brainly.in/question/55839349

https://brainly.in/question/15296853

#SPJ3