Question

There are 7 boys and 7 girls in a class.They sit in a row randomly.What is the chance that all girls donot sit together

Answer 1

The left gaps are possible no. of ways in which girls can sit and Internal arrangement betn boys will take place . Hope u understood the answer. If u want me to elaborate it , feel free to ask in the comments

Answer 2

Answer: Hence, Probability that all girls do not sit together is given by $\frac{19}{33}$

Step-by-step explanation:

Since we have given that

Number of boys = 7

Number of girls = 7

Number of ways in which 7 boys and 7 girls sitting together in a row = 8!

7 girls sitting together in a row = 7!

So, Probability that all girls  sit together is given by

$\frac{8!\times 7!}{12!}\\\\=\frac{14}{33}$

Hence, Probability that all girls do not sit together is given by

$1-\frac{14}{33}\\\\=\frac{19}{33}$