Math, asked by NISHARV4486, 1 year ago

There are 7 children, you are told that youngest child is boy the probability that all of them are boys is one in?

Answers

Answered by chetanapadol1234
1

Answer:

1/64

Step-by-step explanation:

given youngest is boy

remaining 6 children

so one child probability of boy =1/2

for 6 boy = 1/2*1/2*.....6 times

=1/64

required probability is 1/64

Answered by wifilethbridge
1

Answer:

\frac{1}{64}

Step-by-step explanation:

Total No. of children = 7

Youngest child is boy

Now we are supposed to find The probability that all of them are boys .

Since we are given that Youngest child is boy

Total events = {Girl, Boy}=2

Favorable event =Boy=1

Remaining children = 6

So, Probability that all of them are boys = \frac{1}{2} \times \frac{1}{2}\times \frac{1}{2}\times \frac{1}{2}\times \frac{1}{2}\times \frac{1}{2}

                                                                  = \frac{1}{2}^6

                                                                  = \frac{1}{64}

Hence the probability that all of them are boys is \frac{1}{64}

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