Question

there are six apples and six children in a room apple 1 can't be given to either child 1 or child
2 apple 2 must be given either child 3 or 4
every child is to get one apple is how many ways can be distribution will be done​

Answer 1

Given  : here are six apples and six children in a room apple 1 can't be given to either child 1 or child 2

apple 2 must be given either child 3 or 4

every child is to get one apple  

To Find : how many ways can be distribution will be done​

Solution:

Apple 2 must be given either child 3 or 4

Hence 2 ways  :

apple 1 can't be given to either child 1 or child 2  

=> Apple 1 can be given to  (Either 3 or 4) ,  5 , 6  =  3  ways  

Now we left with 4 apples and and 4 child

that means 4 !  = 24 Way

Total Ways of distribution  = 2 * 3 *  24  =  144 Ways

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Answer 2

Step-by-step explanation:

here are six apples and six children in a room apple 1 can't be given to either child 1 or child 2

apple 2 must be given either child 3 or 4

every child is to get one apple

To Find : how many ways can be distribution will be done

Solution:

Apple 2 must be given either child 3 or 4

Hence 2 ways :

apple 1 can't be given to either child 1 or child 2

=> Apple 1 can be given to (Either 3 or 4) , 5 , 6 = 3 ways

Now we left with 4 apples and and 4 child

that means 4 ! = 24 Way

Total Ways of distribution = 2 * 3 * 24 = 144 Ways