Question

u(m/s)=2
a(m/s^)=4
t(sec)=3
v=u+at(m/s)=?​

Answer 1

By using formula:

V=u+at

=2+4×3

=14 m/s

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Answer 2

Answer:

14 m/s

Explanation:

Given :

• Initial velocity = u = 2 m/s

• Acceleration = a = 4 m/s²

• Time taken = t = 3 seconds

To find :

• Final velocity of the object = v

Using the first equation of motion which says :

V=u+at

V=2+4×3

V=2+12

V=14 m/s

The final velocity of the object which has an initial velocity of 2 m/s and acceleration of 4 m/s² for 3 seconds is equal to 14 m/s

More :

• Acceleration formula = (v-u) / t

• Second Equation of motion = s = ut+½at²

• Third equation of motion = v²-u²=2as