There are some chocolates in a box. Each gets 7 chocolates when these chocolates are distributed equally among the students of a class. If there were 5 more students in the class, then each would get 1 chocolate less. Find the number of students in the class.Solve the given sum.
Answers
Answer:
let the no. of chocolates be x
and let the original no. of students be y
therefore, by first condition x/y=7 i.e. x=7y i.e. x-7y=0...........equation no.1
by second condition no. of students become y+5 therefore, x/y+5=6...since each will get one chocolate less therefore 6 to each therefore x=6(y+5) i.e.x=6y+30
therefore, x-6y=30...... equation no.2
now, by elimination method subtract equation 1from2
therefore,. x-6y=30
-(x-7y=0)
i.e. x-6y =30
-x+7y=0
1y=30
therefore,y=30
now by substituting the value of y in equation 1
we get, x-7(30)=0
i.e. x-210=0
therefore, x=210
THEREFORE, TOTAL NO. OF CHOCOLATES ARE 210,
AND ORIGINAL NUMBER OF STUDENTS IS 30.
IF DOUBT IN ANY STEP PLEASE ENQUIRE...........
Answer:
30
Step-by-step explanation:
The number of chocolates a student gets = 7 (Given)
Let the number of students in class be = x
Thus, the number of chocolates when equally distributed = 7 × x = 7x
If there were 5 more students , then each will get one chocolate less.
then, the number of students will be = x+5
Chocolates = 7-1 = 6
Therefore the equation will be
= 6 × (x+5)
= 6x+30
Number of chocolates = 6x+30 and 7x,
Solving both the equations -
= 7x = 6x+30
= 7x - 6x = 30
= x = 30
Therefore, the number of students is 30.