There are two examinations rooms A and B. If 10 students are sent from A to B, then the number of students in each room is the same. If 20 candidates are sent from B to A, then the number of students in A is double the number of students in B. The number of students in room A is:
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Let the number of students in rooms A and B be x and y respectively.
⇒ x - 10 = y + 10 x - y = 20 .... (i)
and x + 20 = 2(y - 20) x - 2y = -60 .... (ii)
bu solving (i) and (ii) we get: x = 100 and y = 80.
∴ A = 100
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