There are two machines in a production house machine A and machine B. Machine A manufactures 200 items and machine B manufactures 100 items out of which 18 and 15 items are found to be defective.
(i) What is the probability of an item being defective if it is manufactured by machine A?
(ii) What is the probability of an item being good if it is manufactured by machine B
Answers
Answered by
1
Answer:
1. Probability = (no. of favourable outcomes) / total no. of outcomes
= 18/200 = 9/100
2.Probability = (no. of favourable outcomes) / total no. of outcomes
= 85/100 = 17/20
Answered by
0
Answer:
(i) 9/100
(ii) 17/20
Step-by-step explanation:
(i) they are asking for defective probability so we have to take 18 defective parts with respect to total 200 items.
= 18/200= 9/100
(ii) they are asking for good item probability so we have to take 85 good parts with respect to total 100 items.
= 85/100= 17/20
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