There are two numbers such that the sum of twice the first and thrice the second is 39, while the sum of thrice the first, and twice the second is 36. The larger of the two is:
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Let the numbers be x and y.
Then, 2x + 3y = 39...(i) and
3x + 2y = 30 ...(ii)
On solving (i) and (ii), we get :
x = 6 and y = 9.
larger number = 9
So the answer would be 9
rikergrace16:
show me how you solved equation 1 and two please
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Answer:
Step-by-step explanation:
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