Question

There are two resistors R1 and R2 having resistance equal to 20Ω and 30Ω respectively are connected in parallel in an electric circuit. If the potential difference across the electric circuit is 5 V, find the electric current flowing through the circuit and the total resistance of the resistors. 

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Answer 1

refers to attachment...

Answer 2

The electric current flowing through the circuit is 0.416 A

The total resistance of the resistors is 12 Ω.

Given: There are two resistors R1 = 20 Ω and R2 = 30 Ω connected in parallel. The potential difference across the electric circuit is 5 V.

To Find: The electric current flowing through the circuit and the total resistance of the resistors.

Solution:

• We know that for 2 resistors connected in parallel, the equivalent resistance is calculated using the formula,

        R = R1 × R2 / ( R1 + R2 )                                           ......(1)

where R1 and R2 = resistors connected in parallel connection.

• We know that according to Ohm's law,

        V = I×R                                                                      ......(2)

Where V = potential difference, I = current, R = equivalent resistance

Coming to the numerical, we are given,

R1 = 20 Ω and R2 = 30 Ω, so putting respective values in (1), we get;

           R = R1 × R2 / ( R1 + R2 )

       ⇒  R = 20 × 30 / ( 20 + 30 )

       ⇒  R = 600 / 50

       ⇒  R = 12 Ω

Now, we need to find the electric current flowing through the circuit, so putting respective values in (2), we get;

             V = I×R  

        ⇒  5 = I × 12

        ⇒  I  = 5/12 A

        ⇒  I  = 0.416 A

Hence, the electric current flowing through the circuit is 0.416 A

            the total resistance of the resistors is 12 Ω.

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