Question

there are two sections A and B in class6 .in section A of 60 students, 30 passed with distinction marks , in sections B of 40 students , 35 passed with distinction marks .in which section has a greater fraction of students getting distinction marks

Answer 1

Here,
Fraction of student getting distinction in section A = 30/60 = 1/2
Fraction of student getting distinction in section B = 35/40 = 7/8

By equating both the fraction as
1/2 *4/4 = 4/8 < 7/8.
So, Section B has a greater fraction of student getting distinction.

Answer 2

heya!

Students passed with distinction in SEC - A => 30/60 = 1/2

Students passed with distinction in SEC - B => 35/40 = 7/8

Now, to compare them, there are two methods!

Cross multiplication -

1 × 8 = 8 [ 1/2 ]
2 × 7 = 14 [ 7/8 ]

Lcm method -

Lcm of denominators ( 2,8 ) = 8

So,
1/2 = 4/8
7/8 = 7/8

Comparison => 4/8 < 7/8

=> 1/2 < 7/8
=> 30/60 < 35/40

hence, SEC - B has more students getting distinction marks.

#hope it helps!