There exists a uniform magnetic and electric field of magnitude 1 t and 1 v/m respectively along positive y-axis. A charged particle of mass 1kg and charge 1c is having velocity 1 m/s along x-axis and is at origin at t=0. Then the coordinates of particle at time pi seconds will be
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Answer:
Since the particle will accelerate along the axis in which
E
is applied, it will have a helical path. The circular path is due to the magnetic field.
T=
qB
2πm
=2πAfter π seconds, the particle will complete half the circle in the z−x plane.
r=
qB
mv
=
1×1
1×1
=1
X−coordinate will be x=0.
Z−coordinate will be z=2r=2
Co-ordinate of the particle along y−axis: y=ut+
2
1
at
2
=0t+
2
1
m
qE
t
2
=
2
1
m
qE
π
2
=
2
π
2
Hence, the co-ordinate of the particle will be (0,
2
π
2
Hope it helps you !!!
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