Math, asked by abhinavmikejeemain, 4 months ago

There is a circular pond and foot-path runs along its boundary. A man walks around exactly once
keeping close to the edge. If his step is 55 cm long and he takes exactly 400 steps to go round the
what is the diameter of the pond? ​

Answers

Answered by Anonymous
3

Answer:

7000 cm

Step-by-step explanation:

Let the radius of the pond be x cm

Circumference = 2\pir

=> 2 × \dfrac{22}{7} × r

=> \dfrac{44}{7} r cm

Length of the step = 55cm

No. of steps = 400

Total distance covered = 400 × 55 = 22000cm

Circumference = total distance covered

\dfrac{44}{7}× r = 22000cm

r = 22000 × \dfrac{7}{44}

=> 3500 cm

diameter = 2r

=> 2 × 3500

=> 7000 cm

Therefore, The diameter is 7000 cm

Answered by beautyqueen1137
4

Answer:

Let the radius of the pond be 'r'. since man takes exactly 400 step of 55 cm to go around the pond.

Hence, the circumference of the pond = 55×400 = 22000 cm

 \frac{22000}{100}

220 m

circumference of the pond is 220m.

circumference of the circular pond =2πr

220=2πr

220= 2×

 \frac{22}{7}

×r

r= 220×

 \frac{7}{44}

r=35m

∴ Diameter of the pond =2×r

=2×35

=70m.

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