Question

There is a rectangular park of length 55

m and breadth 42 m in a JNV. It has small

flower beds in the shape of Trapezium,

Square, Triangle and circle in it as shown in

the figure. The dimensions of these flower

beds are also given. Vidyalaya has planted

Variety of flowers in these flower beds to

beautify it. The figure is given below

Answer the following question :

(i) Which flower bed has more area

Triangle or square ?

(ii) Which flower bed has least area ?

(iii) What is the perimeter of vidyalaya

park ?

(iv) What is cost of planting Jasmine

flower in circular flower bed if it

costs Rs 8 /m2​

Answer 1

Step-by-step explanation:

I) square

ii)circle

III) 97meters

IV)me also don't know

Answer 2

Answer i) :-

→ Area of ∆ = (1/2) * Base * height = (1/2) * 2 * 3.5 = 3.5 m².

→ Area of square = (side)² = (2.5)² = 6.25 m².

therefore, Square bed has more area than triangle.

Answer ii) :-

→ Area of circle = πr² = (22/7) * 2.1 * 2.1 = 22 * 0.3 * 2.1 = 13.86m².

→ Area of trapezium = (1/2)(sum of parallel sides) * height = (1/2) * (2 + 3) * 1.5 = (1/2) * 5 * 1.5 = 2.5 * 1.5 = 3.75 m².

since ,

→ 3.5 < 3.75 < 6.25 < 13.86 .

→ ∆ < trapezium < square < circle .

therefore, triangular flower bed has least area.

Answer iii) :-

→ Perimeter of vidyalaya park = 2(L + B) = 2(55 + 42) = 2 * 97 = 194 m (Ans.)

Answer iv) :-

→ Cost of planting Jasmine flower in circular flower bed = Rate / m² * Area of circular flower bed = 8 * 13.86 = Rs.110.88 (Ans.)

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