Question

There is a rectangular plot, reserved for the construction of a school . The length and breadth of the plot are in the ratio 8:5 . At the rate of ₹ 100 per metres , it will cost ₹ 52000 to fence the plot . What are the dimensions of the plot ?​

Answer 1

Answer:

Hey friend,

Here is the answer you are searching for,

$given \\ cost \: per \: {m} = 100 \\ total \: cost = 52000 \\ = > perimeter \: of \: plot \\ = \frac{52000}{100} = 520 \: {m} \\ let \: length \: and \: breadth \\ \: be \: 8x \: and \: 5x \\ = > perimeter \: of \: rectangle \\ = 2(length + breadth) \\ = > 520 = 2(8x + 5x) \\ = > 520 = 2 \times 13x \\ = > 26x = 520 \\ = > x = \frac{520}{26} = 20m \\ therefore \\ length =8 x = 8 \times 20 = 160m \\ breadth = 5x = 5 \times 20 = 100m$

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Answer 2

Answer :

length of plot is 160 m .

breadth of plot is 100 m .

Step - by - step :

let the length of the rectangular plot be 8x metres

Then

breadth = 5x metres

perimeter = 2(length + breadth).

= 2(8x + 5x) = 26x. ....(1)

₹ 100 is the cost of fencing 1 metre .

₹ 52000 is the cost of fencing

=1/100 × 52000 meters = 520 metres. ...(2)

From (1) and (2) , we get

26x = 520

x = 520 /26 = 20

x = 20

length = 8x metres = ( 8 × 20) m = 160 m

breadth = 5x metres = (5 × 20) m = 100 m

hence, the length of plot is 160 m and its breadth is 100 m .