There is a triangular field in front of a classroom. The two sides which are perpendicular measures 6 m and 8 m. The teacher told students to construct a circular flower bed which touches the three sides of the field. Find the radius of circular flower bed. What values are developed in the students through this activity.
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The perpendicular sides of the triangle are 6 m and 8 m
Therefore, the third side, hypotenuse is 10 m (By Pythagorean theorem)
We also know that, the inradius of the circle is the ratio between its area and the semi-perimeter
r = Δ/s
ARea of the triangle = 1/2 * 6 * 8 = 24 sq m
semi-perimeter, s = (6+8+10)/2 = 12 m
So, r = 24/12 = 2 m
Therefore, the third side, hypotenuse is 10 m (By Pythagorean theorem)
We also know that, the inradius of the circle is the ratio between its area and the semi-perimeter
r = Δ/s
ARea of the triangle = 1/2 * 6 * 8 = 24 sq m
semi-perimeter, s = (6+8+10)/2 = 12 m
So, r = 24/12 = 2 m
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