Math, asked by alok28478, 8 months ago

There is a triangular field of sides 100 m, 250 m & 300 m. A person is standing at the vertex between the two longest sides of this field. Find the shortest distance from the opposite vertex to the side whose length is 100 m.

Answers

Answered by odangerlongkumer
0

Answer:

According to heron's formula A=  

p(p−a)(p−b)(p−c)

​  

 

p=  

2

a+b+c

​  

 

Area of the triangle with wheat=A  

1

​  

 

p  

1

​  

=  

2

360+200+240

​  

=400

A  

1

​  

=  

400(400−200)(400−240)(400−360)

​  

=  

400(200)(160)(40)

​  

=22627.417m  

2

=2.26Hectares

Similarly, Area of triangle 2 is A  

2

​  

 

p  

2

​  

=  

2

320+400+240

​  

=480

A  

2

​  

=  

480(480−240)(480−320)(480−400)

​  

=  

480(240)(160)(80)

​  

=38400m  

2

=3.84Hectares

Half of it is for onions=1.62Hectares, Other half is for potatoes=1.62Hectares

PLZ MAKE ME AS THE BRAINLEST

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