Question

There is certain number of chocolates in a bowl. If 2 boys distribute equally between them, 1
chocolate will be left in the bowl. If 3, 4, 5, 6 and 7 boys distribute equally among them, then
2, 3, 4, 5 and 6 chocolates respectively will be left in the bowl. How many chocolates are
there in the bowl?​

Answer 1

Answer:

Step-by-step explanation:

1 has to be removed from the question or it wont make sense.Assuming 1 is not there the answer is 301.

Let the number of chocolates be n. Then (n-1) has to be divisible by the lcm of 2,3,4,5,6 which is 60. Thus,

(n-1)= 60m. Where m is a natural number.

And (60m+1) is divisible by 7. A little trial and error gives 301 as the answer.

Answer 2

Answer:

63

Step-by-step explanation:

2 = 1 = 3

3 = 2 = 8

4 = 3 = 11

5 = 4 = 14

6 = 5 = 17

7 = 6 = 20

—————

63 chocolate... I think

hope this helps