Question

this is of 8th standard math question I can't solve this. how can I solve this?

Answer 1

p=rs 60000

r=9 p.c.p.a

n=3years

simple interest=p x r x n\100
= 6000x9x3\100
=rs 16200
amount on the same principal at compound interest
amount=p(1+ R\100)N
=60000(1+9\100)3
=(1+9\100)3
=60000(1.09)3
=60000x 1.09x1.09x1.09
60000x1.295029
=rs 77701.74


compount interest=amount - principal
=77701.74-60000
=rs 17701.74



difference= si-ci
=17701.74-16200
=rs 1501.74


and - sunitabai would have to pay rs 1501.74 more as interest