This is urgent please solve this question (q-10)
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(10)
Let the angle be 'x'
And it's complementary angle be (90-x)
According to the question,
The angle differs from its complement by 10°
x - (90-x) = 10
x-90+x = 10
2x-90 = 10
2x = 10+90
2x = 100
x =
x = 50°
∴The angle is 50°
Let the angle be 'x'
And it's complementary angle be (90-x)
According to the question,
The angle differs from its complement by 10°
x - (90-x) = 10
x-90+x = 10
2x-90 = 10
2x = 10+90
2x = 100
x =
x = 50°
∴The angle is 50°
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0
Question:- If an angles differs from its complement by 10°,find the angle ...
Let the angle & its complement are x,x+10
x+(x+10)=90
2x+10=90
x=40°
There fore ,angle & complement are 40°,50° respectively .
Let the angle & its complement are x,x+10
x+(x+10)=90
2x+10=90
x=40°
There fore ,angle & complement are 40°,50° respectively .
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