three angles of a quadrilateral are in the ratio of 2:3:5. the sum of the least and the greatest angle is 150. find the angles of the quadrilateral
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Let the ratio be x, 2x,3x and 5x(since,there is four side in quadrilateral and three ratios are given)
so,
A/Q
x+2x+3x+5x=360
=x+3x+150=360 (Given least and grwatest angle =150)
=4x+150=360
=4x=360-150
=4x=210
=x=210/4
=x=52.5
A/Q,
3x=52.5*2
=157.5
2x+5x=150. (Given)
=7x=150
x=150/7
x=21.428
2x=2*21.428
=42.856
5x=5*21.428
=107.140
So amgles are-52.5 ,157.5 ,21.428 ,107.140.
so,
A/Q
x+2x+3x+5x=360
=x+3x+150=360 (Given least and grwatest angle =150)
=4x+150=360
=4x=360-150
=4x=210
=x=210/4
=x=52.5
A/Q,
3x=52.5*2
=157.5
2x+5x=150. (Given)
=7x=150
x=150/7
x=21.428
2x=2*21.428
=42.856
5x=5*21.428
=107.140
So amgles are-52.5 ,157.5 ,21.428 ,107.140.
Sidjain411:
at last thrw is angle not amgles. sorry for that
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