three angles of a seven sided polygon are 132° each and the remaining four angles are equal. Find the value of each equal angle.
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Three angles are 44deg and remaining four are 34deg
jjangjjangmanboong:
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Let the other 4 equal angle be x°
Now sum of angles of heptagon
(Number of sides-2)×180°
(7-2)×180°=900
Sum of angles =900
3(132)°+4x°=900°
4x°=900-396
x°=504/4
x°=126
Now sum of angles of heptagon
(Number of sides-2)×180°
(7-2)×180°=900
Sum of angles =900
3(132)°+4x°=900°
4x°=900-396
x°=504/4
x°=126
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