Three bells ring simultaneously at 11:00 am .They ring at regular intervals of 20min, 30min and 40 min respectively. Find the time when all the three will ring together again.
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Answer:
Required time = LCM of 20 30 and 40
= 2 x 2 x 2 x 3 x 5 = 120
120 min = 2 hours
Thus, the bell will ring simultaneously after 2 hours = 1:00 pm
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