Question

three Bells rings at an interval interval of 20 minutes 25 minutes and 30 minutes respectively if the Rings together at 11 a.m at what time they will ring together again

Answer 1

To find the minimum time,we have to find the LCM of 20,25,30
20=2*2*5
25=5*5
30=3*2*5
LCM =2*2*3*5*5
=300 minutes
=5 hours
therefore,at 4 p.m, they will meet again

Answer 2

Answer:

Step-by-step explanation:

find lcm of 20,25,30

lcm300

since the given numbers are minutes, lcm is also minute

(ie) 300 min

1hr=60min

1min=1/60hr

300min=300/60

            =5hr

the bell rang at 11 am so next they will ring in 5hrs

11+5

16:00  =  4:00pm