Three circles touch each other pairwise
externally. If the distance between their centres
is 5 cm, 6 cm and 7 cm. Find their radii.
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Step-by-step explanation:
ANSWER
Here,given
a=1
d=4−1=3
and,s
n
=287
Now,
s
n
=
2
n
(2a+(n−1)d)
⇒287=
2
n
(2×1+(n−1)3)
⇒287=
2
n
(2+3n−3)
⇒574=n(3n−1)
⇒574=3n
2
−n
⇒3n
2
−n−574=0
onsolvingthequadraticequatonusingformula
n=
2a
−b±
b
2
−4ac
Wegetn=14&
3
−41
[doesnotexist]
so,n=14
Now,
s
n
=
2
n
(a+1)
⇒287=
2
14
(1+x)
⇒574=14(1+x)
⇒(1+x)=
14
574
⇒1+x=41
⇒x=41−1
∴x=40
x=40isthesolution.
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