Question

three consecutive even integers have a sum of 18. find the integers

Answer 1

x+x+2+x+4=18
3x+6=18
3x=18-6
3x=12
x=12/3
x=4
the numbers are x ,x+2 ,x+4
therefore the numbers are 4, 4+2 ,4+4
4,6,8

Answer 2

first even number is x
second even number is x+2
third even number is x+4
so,equation is
x+(x+2)+(x+4)=18
3x+6=18
3x=18-6
3x=12
x=12/3
x=4
first number=4
second number=(x+2)=4+2=6
third even number=(x+4)=4+4=8
checking the answer= 4+6+8=18
answer is proved