Question

Three consecutive integers. Are such that when taken in ascending order and multiplied by 2,4 and 6,respectively their sum is 160.find the integers

Answer 1

Three consecutive intergers can be expressed as x , x+1 and x+2.

Therefore,
According to the question.
(x × 2) + 4(x + 1) + 6(x +2) = 160
Therefore,
2x + 4x + 4 + 6x + 12 = 160
12x + 16 = 160
12x = 160 - 16
12x = 144
x = 12

Therefore the intergers are x, x+1 and x +2.
The intergers are 12, (12 + 1), (12 + 2).
The intergers are 12, 13 and 14.

Answer 2

Let the three consecutive integers be x , x + 1, x + 2.

Given that when taken in A.O and multiplied by 2,4,6 their sum = 160

2(x) + 4(x + 1) + 6(x + 2) = 160

2x + 4x + 4 + 6x + 12 = 160

12x + 16 = 160

12x = 160 - 16

12x = 144

x = 12.

So the integers are:

x + 1 = 12 + 1 = 13.

x + 2 = 12 + 2 = 14.


Therefore the integers are 12,13,14.


Verification:

12 * 2 + 13 * 4 + 14 * 6

= 24 + 52 + 84

= 160.


Hope this helps!