Question

Three consecutive integers are such that when they are taken in increasing order and
multiplied by 2, 3 and 4 respectively, they add up to 74. Find these number​

Answer 1

Step-by-step explanation:

hope this will help you dear

Answer 2

Solution :

$\bf{\red{\underline{\bf{Given\::}}}}$

Three consecutive integers are such that when they taken in increasing order and multiplied by 2,3 and 4 respectively, they add up to 74.

$\bf{\red{\underline{\bf{To\:find\::}}}}$

These number.

$\bf{\red{\underline{\bf{Explanation\::}}}}$

Let the three consecutive integers be x, x+1, and x+2.

A/q

$\longrightarrow\sf{2\times x+3(x+1)+4(x+2)=74}\\\\\\\longrightarrow\sf{2x+3x+3+4x+8=74}\\\\\\\longrightarrow\sf{9x+11=74}\\\\\\\longrightarrow\sf{9x=74-11}\\\\\\\longrightarrow\sf{9x=63}\\\\\\\longrightarrow\sf{x=\cancel{\dfrac{63}{9} }}\\\\\\\longrightarrow\sf{\pink{x=7}}$

Thus;

$\bullet\sf{1_{st}\:number=x=\boxed{7}}}\\\bullet\sf{2_{nd}\:number=(x+1)=7+1=\boxed{8}}}\\\bullet\sf{3_{rd}\:number=(x+2)=7+2=\boxed{9}}}$