Question

three consecutive integers are such that when they are taken in increasing order and multiplied by 2,3,4 respectively they add up to 74 , find these numbers​

Answer 1

Answer:

1st no. = 7 ,2nd no. = 8 , 3rs no. = 9

Explanation:

Let the 1st no. be x, then

2nd no. = x+1

3rd no. = x+1+1= x+2

ATQ, 2 (x) + 3(x+1) + 4( x+2)= 74

2x+ 3x+3 + 4x+ 8 = 74

9x+11= 74

9x= 74-11

x= 63/9

x= 7

x= 7, x+1 =8, x+2 = 9

Answer 2

Answer:

7, 8, 9

Step-By-Step Explanation:

Let the three consecutive integers are x, x+1 and x+2.

According to the question,

2x + 3(x+1) + 4(x+2) = 74

⇒ 2x + 3x +3 + 4x + 8 = 74

⇒ 9x + 11 = 74

⇒ 9x = 74 – 11

⇒ 9x = 63

⇒ x = 63/9

⇒ x = 7

Thus, the numbers are:

x = 7

x + 1 = 8

x + 2 = 9