Math, asked by dabbi9173, 8 months ago

Three consecutive multiples of five have a sum of 75. what are the numbers?

Answers

Answered by superlucky04
0

Answer:

here is it see

Step-by-step explanation:

x+(x+5)+(x+10) = 75

3x+15=75

3x = 75- 15

3x=60

x=60/3

x=20

x=20

(x+5)=20+5=25

(x+10)=20+10=30

Mark me as BRAINLEST ANSWER kkkkk

Answered by SerenaBochenek
0

The three numbers are "20", "25" and "30".

Step-by-step explanation:

Let \ the \ three \ consecutive \ multiple \ of \ 5 \ be:\\The \ first \ number=x\\The \ second \ number=(x+5)\\The \ third \ number=(x+10)\\The \ sum =75\\According \ to \ the \ question,\\x+x+5+x+10=75\\3x+15=75\\On \ subtracting \ "15" \ from \ both \ sides,we \ get\\3x+15-15=75-15\\3x=60\\x=\frac{60}{3}\\ x=20\\The \ first \ number=x=20\\The \ second \ number = x+5=25\\The \ third \ number=x+10=30

Learn more:

https://brainly.in/question/15533488

Similar questions