Question

Three consecutive odd integers are in decreasing order such that the sum of the last two integers is 25 more than the first integer. Find the sum of the three integers?​

Answer 1

Answer:

87

Step-by-step explanation:

Let the three numbers be ,

(2n+3),(2n+1),(2n-1),

A. ,. B. ,. C.

Given that , A+25 = B+C

2n+3+25=2n+1+2n-1

28= 4n=> n=14

three numbers are => A= 2n+3= 31

B=2n+1= 29

C=2n-1= 27

Sum = 87