Question

Three consecutive odd integers are such that the sum of the first and second is 31 less than 3 times the third. Find the integers.

Answer 1

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This can be done with two process:-

1st process :-

Let's first odd integer = x

Then next consecutive int. = x+2, x+4

(x)+(x+4) = (x+2)+(x+2)+(x+2) - 131

2x + 4 = (3x + 6) - 131

x - 129 = 0

x = 129

Three integer are = 129, 131, 133

2nd process :-

Let the three consecutive odd integers be x-2, x, x+2

So (x-2)+(x+2) = 3x - 131

=> 2x = 3x-131 => 3x-2x = 131 => x = 131

So the three odd integers are 131–2, 131, 131+2

ie. 129,131,133.

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Answer 2

Hope this helps .........