three consecutive odd numbers whose sum is 45 are =
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Let the three consecutive odd numbers be:
2x + 1, 2x + 3 , 2x + 5
According to the question:
==> 2x + 1 + 2x + 3 + 2x + 5 = 45
==> 6x + 9 = 45
==> 3(2x + 3) = 45
==> 2x + 3 = 15
==> 2x = 12
==> x = 6
Numbers are 2x + 1 , 2x + 3, 2x + 5
So,
==> 2x + 1 = 2(6) + 1 = 13
==> 2x + 3 = 2(6) + 3 = 15
==> 2x + 5 = 2(6) + 5 = 17
Hence, The numbers are 13 , 15 and 17
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