Question

Three consicutive even numbers are such that the largest of them is twice the smallest. Find the second largest number among the three​

Answer 1

Answer:

let's say "n" is a natural number. {1,2,3,4,..} To ensure we have an even number we will multiply "n" by 2. Two times any number will make an even number.

consecutive even numbers are like; 2, 4, 6, 8, 10 .. etc. Add +2 to the previous number to get the next consecutive.

1st even number = 2n

2nd even number = 2n + 2

3rd even number = 2n + 4

twice the first number (2n) is 20 more then the second (2n + 2).

2(2n) = 2n + 2 + 20

4n = 2n + 22

4n - 2n = 22

2n = 22

n = 11

Now use n = 11 to find the 3 consecutive even numbers.

1st even number = 2(11) = 22

2nd even number = 2(11) + 2 = 24

3rd even number = 2(11) + 4 = 26

22, 24, 26

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