three cubes each of side 6 CM are joined end to end find the surface area of the resulting cuboid
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Answered by
7
l= l+l+l
= 6+6+6
=18 cm
surface area of cuboid = 2(lb+bh+lh)
= 2(18*6+6*6+18*6)
= 2(108+36+108)
= 504sqcm.
= 6+6+6
=18 cm
surface area of cuboid = 2(lb+bh+lh)
= 2(18*6+6*6+18*6)
= 2(108+36+108)
= 504sqcm.
Answered by
3
Answer:
If you join the cubes to form a cuboid,
The length of the cuboid will become 6×3=18cm
While the breadth and height will remain same.
So, surface area=2(lb+bh+hl)
=2(18×6+18×6+6×6)
=2(108+108+36)
=2(252)
=504cmsq. ......
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