Question

Three dice are rolled. Find the number of possible outcomes in which at least one dice shows 5

Answer 1

Answer:

'5' appear once: $^3C_1\cdot 6^2=108$

'5' appear twice: $^3C_2\cdot 6=18$

'5' appear thrice: $^3C_3=1$

Total number of possible outcomes=108+18+1=127

Hope this helps :)

Step-by-step explanation: