Question

Three equal charges +q are placed on the corners of an equilateral triangle of side a.Then the couloumb force experienced by one charge due to the rest of the two is?

Answer 1

PUT HC VERMA QUESTIONS ......FOR THE USAGE OF BRAIN.....AND CONCEPTS

Answer 2

Answer:

The net coulomb force experienced by one charge due to the rest of the two is√3 F.

Explanation:

Given that,

Three equal charges +q are placed on the corners of an equilateral triangle of side a.

The coulomb force is defined as:

$F = \dfrac{kq_{1}q_{2}}{r^2}$

Here, $q_{1}=q_{2}$ = charge

Distance = r

Therefore,

The force experienced by q₁ charge due to the rest of the two charges is F₁.

The force experienced by q₂ charge due to the rest of the two charges is F₂.

The force experienced by q₃ charge due to the rest of the two charges is F₃.

Three charges and the distance between the charges are same then the force will be same .

So, F₁=F₂=F₃=F

Angle = 60°

The resultant force is

$F_{net}=\sqrt{F_{1}^2+F_{2}^2+2F_{1}F_{2}cos\theta}$

$F_{1}=F_{2}$

$F_{net}=\sqrt{F^2+F^2+2F\times Fcos60^{\circ}}$

$F_{net}=\sqrt{F^2+F^2+2F\times F\times\dfrac{1}{2}}$

$F_{net}=\sqrt{F^2+F^2+F^2}$

$F_{net}=\sqrt{3F^2}$

$F_{net}=F\sqrt{3}$

Hence, The net coulomb force experienced by one charge due to the rest of the two is√3 F.