Question

Three identical particles are joined together by a thread as shown in figure. All the three particles are moving in a horizontal plane. If the velocity of the outermost particle is v', then the ratio of tension in the three sections of the string is

Answer 1

According to the question we  know that we have to find the ratio of tension in the three section of string.
 so let's suppose angular speed of thread is equal to "W"
by each strings length.
in case of particle C=     T3=mW²3l.
in case of particle B = T2- T3= mW²3l.  so T2=mW²5l
in case of particle A= T1- T2 =mW²2l    so T1=mW²6l.

 Hence the ratio will 3:5:6. which is our answer

Answer 2

Hope the figure comfortable to you to understand

Hope u can understand