Question

Three identical spheres each of radius r and mass m are placed touching each other on a horizontal floor.Locate the position of centre of mass of the system.

Answer 1

Let the mass of sphere is 'm' and center of mass is at a distance xm away from the center of A.
Now,
X=ΣmiXiΣ/mi =m(x)+m(2R-X)+M(4R-x)/3= m(-x+6R)/3m=-X+X/3=2R
X=1.5R
SO, the center of mass will be at a point 1.5 times of radius distant from the center of sphere A.

Answer 2

Answer:

Explanation

here is the explanation